What are the solutions to the equation 5x^2+12x=9 ?

The solutions to the equation 5x^2+12x=9 are x= 3/5 ,x=-3

Find the zeros of 5x^2+12x=9

The zeros of 5x^2+12x=9 are x= 3/5 ,x=-3

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5 x^{2} + 12 x = 9

x = \frac{3}{5}, x = - 3

Decimal Notation

x = 0.6, x = - 3

Solution steps

5 x^{2} + 12 x = 9

Move

9

to the left side

5 x^{2} + 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 5 ( - 9 )}{2 \cdot 5}

1 2^{2} - 4 \cdot 5 (- 9) = 18

x_{1, 2} = \frac{- 12 \pm 18}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 12 + 18}{2 \cdot 5}, x_{2} = \frac{- 12 - 18}{2 \cdot 5}

x = \frac{- 12 + 18}{2 \cdot 5} : \frac{3}{5}

x = \frac{- 12 - 18}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - 3

\frac{13}{2} - 3

5 x^{2} - 29 x - 6

t^{2} + 9 t + 20 = 0

x (6 x + 1) \leq 2

2 y^{2} + 5 y + 2

What are the solutions to the equation 5x^2+12x=9 ?
The solutions to the equation 5x^2+12x=9 are x= 3/5 ,x=-3
Find the zeros of 5x^2+12x=9
The zeros of 5x^2+12x=9 are x= 3/5 ,x=-3