What is (-32x^{10}y^{35})^{-1/5} ?

The solution to (-32x^{10}y^{35})^{-1/5} is -1/(2x^2y^7)

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simplify (-32x^{10}y^{35})^{-1/5}

simplify

(- 32 x^{10} y^{35})^{- \frac{1}{5}}

- \frac{1}{2 x ^{2} y ^{7}}

Solution steps

(- 32 x^{10} y^{35})^{- \frac{1}{5}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(- 32 x^{10} y^{35})^{- \frac{1}{5}} = \frac{1}{( - 32 x ^{10} y ^{35} ) ^{\frac{1}{5}}}

= \frac{1}{( - 32 x ^{10} y ^{35} ) ^{\frac{1}{5}}}

Simplify

(- 32 x^{10} y^{35})^{\frac{1}{5}} : - 2 x^{2} y^{7}

= \frac{1}{- 2 x ^{2} y ^{7}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{1}{2 x ^{2} y ^{7}}

(\frac{5}{x ^{3}} + \frac{8}{x ^{2}})^{2}

5 6 x + 7 3 x - 2 12 x

(x + 1)^{2} - 1

(3 pq)^{\frac{2}{5}}

e^{l n (7 x)}

What is (-32x^{10}y^{35})^{-1/5} ?
The solution to (-32x^{10}y^{35})^{-1/5} is -1/(2x^2y^7)