What is (x^2-9)/(x^2+4x+3) ?

The solution to (x^2-9)/(x^2+4x+3) is (x-3)/(x+1)

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simplify (x^2-9)/(x^2+4x+3)

simplify

\frac{x ^{2} - 9}{x ^{2} + 4 x + 3}

\frac{x - 3}{x + 1}

Solution steps

\frac{x ^{2} - 9}{x ^{2} + 4 x + 3}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{x ^{2} + 4 x + 3}

Factor

x^{2} + 4 x + 3 : (x + 1) (x + 3)

= \frac{( x + 3 ) ( x - 3 )}{( x + 1 ) ( x + 3 )}

Cancel the common factor:

x + 3

= \frac{x - 3}{x + 1}

\frac{x ^{2} - 4}{x ^{2} + x - 6}

15 \cdot 5 \cdot 27

\frac{( 2 p ^{3} ) ^{2}}{10 p ^{3}}

(2 y^{3} - 2 y)^{3}

(a + 2) (3 a - 4)