What are the solutions to the equation X(2X-3)-3(5-X)=83 ?

The solutions to the equation X(2X-3)-3(5-X)=83 are X=7,X=-7

Find the zeros of X(2X-3)-3(5-X)=83

The zeros of X(2X-3)-3(5-X)=83 are X=7,X=-7

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X (2 X - 3) - 3 (5 - X) = 83

X = 7, X = - 7

Solution steps

X (2 X - 3) - 3 (5 - X) = 83

Expand

X (2 X - 3) - 3 (5 - X) : 2 X^{2} - 15

2 X^{2} - 15 = 83

Move

83

to the left side

2 X^{2} - 98 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 ( - 98 )}{2 \cdot 2}

0^{2} - 4 \cdot 2 (- 98) = 28

X_{1, 2} = \frac{- 0 \pm 28}{2 \cdot 2}

Separate the solutions

X_{1} = \frac{- 0 + 28}{2 \cdot 2}, X_{2} = \frac{- 0 - 28}{2 \cdot 2}

X = \frac{- 0 + 28}{2 \cdot 2} : 7

X = \frac{- 0 - 28}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

X = 7, X = - 7

4 x^{2} = 6 x - 1

9 b - 3 b^{2}

6 (x + 18) = 9 x

1 - (- 1)

\frac{12}{1 2 ^{5}}

What are the solutions to the equation X(2X-3)-3(5-X)=83 ?
The solutions to the equation X(2X-3)-3(5-X)=83 are X=7,X=-7
Find the zeros of X(2X-3)-3(5-X)=83
The zeros of X(2X-3)-3(5-X)=83 are X=7,X=-7