What are the solutions to the equation 2=9((x+2)^2)-4 ?

The solutions to the equation 2=9((x+2)^2)-4 are x=sqrt(2/3)-2,x=-sqrt(2/3)-2

Find the zeros of 2=9((x+2)^2)-4

The zeros of 2=9((x+2)^2)-4 are x=sqrt(2/3)-2,x=-sqrt(2/3)-2

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2 = 9 ((x + 2)^{2}) - 4

x = \frac{2}{3} - 2, x = - \frac{2}{3} - 2

Decimal Notation

x = - 1.18350 \dots, x = - 2.81649 \dots

Solution steps

2 = 9 ((x + 2)^{2}) - 4

Switch sides

9 ((x + 2)^{2}) - 4 = 2

Move

4

to the right side

9 (x + 2)^{2} = 6

Divide both sides by

9

(x + 2)^{2} = \frac{2}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = \frac{2}{3} : x = \frac{2}{3} - 2

Solve

x + 2 = - \frac{2}{3} : x = - \frac{2}{3} - 2

The solutions to the quadratic equation are:

x = \frac{2}{3} - 2, x = - \frac{2}{3} - 2

\frac{5 π}{12} \cdot \frac{180}{π}

- 169

2 x^{2} - x - 6 > 0

(1)^{- 1}

1 0^{- 14} = (4 \cdot 1 0^{- 8} + x) x

What are the solutions to the equation 2=9((x+2)^2)-4 ?
The solutions to the equation 2=9((x+2)^2)-4 are x=sqrt(2/3)-2,x=-sqrt(2/3)-2
Find the zeros of 2=9((x+2)^2)-4
The zeros of 2=9((x+2)^2)-4 are x=sqrt(2/3)-2,x=-sqrt(2/3)-2