What is expand (x+2)(x+3)(x-1) ?

The solution to expand (x+2)(x+3)(x-1) is x^3+4x^2+x-6

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expand (x+2)(x+3)(x-1)

expand

(x + 2) (x + 3) (x - 1)

x^{3} + 4 x^{2} + x - 6

Solution steps

(x + 2) (x + 3) (x - 1)

Expand

(x + 2) (x + 3) (x - 1) : (x^{2} + 5 x + 6) (x - 1)

= (x^{2} + 5 x + 6) (x - 1)

Distribute parentheses

= x^{2} x + x^{2} (- 1) + 5 xx + 5 x (- 1) + 6 x + 6 (- 1)

Simplify

x^{2} x + x^{2} (- 1) + 5 xx + 5 x (- 1) + 6 x + 6 (- 1) : x^{3} + 4 x^{2} + x - 6

= x^{3} + 4 x^{2} + x - 6

e^{i 4 π}

lo g_{4} (\frac{17}{8})

(6 a)^{0}

1 \cdot (- x)

9 \cdot \frac{5}{3}

What is expand (x+2)(x+3)(x-1) ?
The solution to expand (x+2)(x+3)(x-1) is x^3+4x^2+x-6