What is 90/51*41/108*34/82 ?

The solution to 90/51*41/108*34/82 is 5/18

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simplify 90/5141/10834/82

simplify

\frac{90}{51} \cdot \frac{41}{108} \cdot \frac{34}{82}

\frac{5}{18}

Solution steps

\frac{90}{51} \cdot \frac{41}{108} \cdot \frac{34}{82}

Cancel

\frac{90}{51} : \frac{30}{17}

= \frac{30}{17} \cdot \frac{41}{108} \cdot \frac{34}{82}

Cancel

\frac{34}{82} : \frac{17}{41}

= \frac{30}{17} \cdot \frac{41}{108} \cdot \frac{17}{41}

Cross-cancel common factor:

17

= \frac{30}{41} \cdot \frac{41}{108}

Cross-cancel common factor:

41

= \frac{30}{108}

Factor the number:

30 = 6 \cdot 5

= \frac{6 \cdot 5}{108}

Factor the number:

108 = 6 \cdot 18

= \frac{6 \cdot 5}{6 \cdot 18}

Cancel the common factor:

6

= \frac{5}{18}

(2)^{1}

7 1^{2}

(\frac{8}{8 - x ^{3}} + \frac{x}{x - 2} - 1) \cdot (\frac{x}{x + 2} - \frac{x + 2}{x})

(3 x^{2} y^{4} - 3 y z^{2}) (- 3 x^{2} y^{4} - 3 y z^{2})

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