What is (x^2-2x-3)/(x^2-1) ?

The solution to (x^2-2x-3)/(x^2-1) is (x-3)/(x-1)

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simplify (x^2-2x-3)/(x^2-1)

simplify

\frac{x ^{2} - 2 x - 3}{x ^{2} - 1}

\frac{x - 3}{x - 1}

Solution steps

\frac{x ^{2} - 2 x - 3}{x ^{2} - 1}

Factor

x^{2} - 2 x - 3 : (x + 1) (x - 3)

= \frac{( x + 1 ) ( x - 3 )}{x ^{2} - 1}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{( x + 1 ) ( x - 3 )}{( x + 1 ) ( x - 1 )}

Cancel the common factor:

x + 1

= \frac{x - 3}{x - 1}

2 (3 y + 1)

\frac{3}{5} \cdot \frac{5}{9}

6 \frac{2}{3} \div 9.25

- \frac{2}{3} \cdot (- \frac{1}{6})