What is (x^2-4x+3)/(x^2+3x-4) ?

The solution to (x^2-4x+3)/(x^2+3x-4) is (x-3)/(x+4)

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simplify (x^2-4x+3)/(x^2+3x-4)

simplify

\frac{x ^{2} - 4 x + 3}{x ^{2} + 3 x - 4}

\frac{x - 3}{x + 4}

Solution steps

\frac{x ^{2} - 4 x + 3}{x ^{2} + 3 x - 4}

Factor

x^{2} - 4 x + 3 : (x - 1) (x - 3)

= \frac{( x - 1 ) ( x - 3 )}{x ^{2} + 3 x - 4}

Factor

x^{2} + 3 x - 4 : (x - 1) (x + 4)

= \frac{( x - 1 ) ( x - 3 )}{( x - 1 ) ( x + 4 )}

Cancel the common factor:

x - 1

= \frac{x - 3}{x + 4}

(r + 6)^{2} + (14 r - 11 + r^{2})

\frac{4}{5} \cdot 100

(4 x + 3)^{2}

\frac{4}{5} \div \frac{3}{5}

(7 a - 4 b + 5 c) + (- 7 a + 4 b - 6 c)

What is (x^2-4x+3)/(x^2+3x-4) ?
The solution to (x^2-4x+3)/(x^2+3x-4) is (x-3)/(x+4)