What is (x-2)/(x-1/(1-\frac{2){x+2)}} ?

The solution to (x-2)/(x-1/(1-\frac{2){x+2)}} is x/(x+1)

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simplify (x-2)/(x-1/(1-\frac{2){x+2)}}

simplify

\frac{x - 2}{x - \frac{1}{1 - \frac{2}{x + 2}}}

\frac{x}{x + 1}

Solution steps

\frac{x - 2}{x - \frac{1}{1 - \frac{2}{x + 2}}}

Simplify

x - \frac{1}{1 - \frac{2}{x + 2}} : \frac{x ^{2} - x - 2}{x}

= \frac{x - 2}{\frac{x ^{2} - x - 2}{x}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{( x - 2 ) x}{x ^{2} - x - 2}

Cancel

\frac{( x - 2 ) x}{x ^{2} - x - 2} : \frac{x}{x + 1}

= \frac{x}{x + 1}

38 \cdot 3

(- 7 x^{2} y^{5} z) (- 2 x^{6} y^{2}) (- 4 x yz)

\frac{\frac{1}{4} \cdot \frac{1}{x} \cdot y ^{\frac{3}{2}}}{3 ^{- \frac{1}{4}} \cdot x \cdot y ^{- \frac{1}{4}}}

\frac{100}{25} + \frac{36}{9}

6 \cdot \frac{1}{8}

What is (x-2)/(x-1/(1-\frac{2){x+2)}} ?
The solution to (x-2)/(x-1/(1-\frac{2){x+2)}} is x/(x+1)