What is factor 25y^2-10y+1 ?

The solution to factor 25y^2-10y+1 is (5y-1)^2

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factor 25y^2-10y+1

factor

25 y^{2} - 10 y + 1

(5 y - 1)^{2}

Solution steps

25 y^{2} - 10 y + 1

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

25 y^{2} = (5 y)^{2}

1 = 1^{2}

- 10 y = - 2 \cdot 5 y \cdot 1

= (5 y)^{2} - 2 \cdot 5 y \cdot 1 + 1^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(5 y)^{2} - 2 \cdot 5 y \cdot 1 + 1^{2} = (5 y - 1)^{2}

= (5 y - 1)^{2}

\frac{5 x ^{4} - 3 x ^{3} + 2 x ^{2} - 7 x + 3}{x - 1}

\frac{y ^{5}}{y ^{5}}

sec^{2} (- tan^{2} (x))

\frac{- 3 ( t ) ^{2}}{- 12 t ^{- 4}}

- \frac{( - 1 ) ^{3}}{3}