What is ((6x+6)/7)/(\frac{4x+4){x-2}} ?

The solution to ((6x+6)/7)/(\frac{4x+4){x-2}} is (3(x-2))/(14)

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simplify ((6x+6)/7)/(\frac{4x+4){x-2}}

simplify

\frac{\frac{6 x + 6}{7}}{\frac{4 x + 4}{x - 2}}

\frac{3 ( x - 2 )}{14}

Solution steps

\frac{\frac{6 x + 6}{7}}{\frac{4 x + 4}{x - 2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( 6 x + 6 ) ( x - 2 )}{7 ( 4 x + 4 )}

Cancel

\frac{( 6 x + 6 ) ( x - 2 )}{7 ( 4 x + 4 )} : \frac{3 ( x - 2 )}{14}

= \frac{3 ( x - 2 )}{14}

\frac{1}{16} \cdot \frac{1}{2}

72 \cdot (- 0.0673)

(2 - 6 i) (7 + i)

2 3^{0}

2 x^{2} + 14 x - 60

What is ((6x+6)/7)/(\frac{4x+4){x-2}} ?
The solution to ((6x+6)/7)/(\frac{4x+4){x-2}} is (3(x-2))/(14)