What is the domain of f(a)=(27a^3-1)/(9a^2-6a+1) ?

The domain of f(a)=(27a^3-1)/(9a^2-6a+1) is a 1/3

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domain of f(a)=(27a^3-1)/(9a^2-6a+1)

domain

f (a) = \frac{27 a ^{3} - 1}{9 a ^{2} - 6 a + 1}

a < \frac{1}{3} or a > \frac{1}{3}

Interval Notation

(- \infty, \frac{1}{3}) \cup (\frac{1}{3}, \infty)

Solution steps

Find undefined (singularity) points:

a = \frac{1}{3}

The function domain

a < \frac{1}{3} or a > \frac{1}{3}

\frac{\frac{4 x - 24}{- 3 x - 15}}{\frac{x ^{2} - 36}{x + 5}}

\frac{4}{3} (- 6 Y)

\frac{1}{x - 1} + \frac{1}{( x - 1 ) ^{2}} + \frac{x}{x ^{2} - 1}

1 0^{- 6} \cdot 1 0^{- 6}

f (x) = 3 x e^{\frac{1}{2} x} d x

What is the domain of f(a)=(27a^3-1)/(9a^2-6a+1) ?
The domain of f(a)=(27a^3-1)/(9a^2-6a+1) is a< 1/3 \lor a> 1/3