What is expand (5m^3n-3m^4p+6m^2)(8mp^3) ?

The solution to expand (5m^3n-3m^4p+6m^2)(8mp^3) is 40m^4p^3n-24m^5p^4+48m^3p^3

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expand (5m^3n-3m^4p+6m^2)(8mp^3)

expand

(5 m^{3} n - 3 m^{4} p + 6 m^{2}) (8 m p^{3})

40 m^{4} p^{3} n - 24 m^{5} p^{4} + 48 m^{3} p^{3}

Solution steps

(5 m^{3} n - 3 m^{4} p + 6 m^{2}) (8 m p^{3})

= (8 m p^{3}) (5 m^{3} n - 3 m^{4} p + 6 m^{2})

Apply the distributive law:

m (a + b + c) = ma + mb + m c

(8 m p^{3}) (5 m^{3} n - 3 m^{4} p + 6 m^{2}) = 8 m p^{3} \cdot 5 m^{3} n + 8 m p^{3} (- 3 m^{4} p) + 8 m p^{3} \cdot 6 m^{2}

= 8 m p^{3} \cdot 5 m^{3} n + 8 m p^{3} (- 3 m^{4} p) + 8 m p^{3} \cdot 6 m^{2}

Simplify

8 m p^{3} \cdot 5 m^{3} n + 8 m p^{3} (- 3 m^{4} p) + 8 m p^{3} \cdot 6 m^{2} : 40 m^{4} p^{3} n - 24 m^{5} p^{4} + 48 m^{3} p^{3}

= 40 m^{4} p^{3} n - 24 m^{5} p^{4} + 48 m^{3} p^{3}

(k^{3})^{5}

x sin (x) (2 x)

\frac{2 ( 1 ) ^{\frac{3}{2}}}{3}

35.85 + 0.023 (15.52)

\frac{1 + tan ^{2} ( x )}{1 - tan ^{2} ( x )}

What is expand (5m^3n-3m^4p+6m^2)(8mp^3) ?
The solution to expand (5m^3n-3m^4p+6m^2)(8mp^3) is 40m^4p^3n-24m^5p^4+48m^3p^3