What is (x+1)^2-(x+1)-6 ?

The solution to (x+1)^2-(x+1)-6 is x^2+x-6

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simplify (x+1)^2-(x+1)-6

simplify

(x + 1)^{2} - (x + 1) - 6

x^{2} + x - 6

Solution steps

(x + 1)^{2} - (x + 1) - 6

Apply the distributive law:

- (a + b) = - a - b

- (x + 1) = - x - 1

= (x + 1)^{2} - x - 1 - 6

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

= x^{2} + 2 x + 1 - x - 1 - 6

Group like terms

= x^{2} + 2 x - x + 1 - 1 - 6

Add similar elements:

2 x - x = x

= x^{2} + x + 1 - 1 - 6

Subtract the numbers:

1 - 1 - 6 = - 6

= x^{2} + x - 6

\frac{5}{3 - 1}

16 i

\frac{x + 2}{x ^{3} + 8}

- ∣ - 3 ∣

4.6