What is (4w^2+17)-(w^2+5w-4) ?

The solution to (4w^2+17)-(w^2+5w-4) is 3w^2-5w+21

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simplify (4w^2+17)-(w^2+5w-4)

simplify

(4 w^{2} + 17) - (w^{2} + 5 w - 4)

3 w^{2} - 5 w + 21

Solution steps

(4 w^{2} + 17) - (w^{2} + 5 w - 4)

Apply rule:

(a) = a

(4 w^{2} + 17) = 4 w^{2} + 17

= 4 w^{2} + 17 - (w^{2} + 5 w - 4)

Apply the distributive law:

- (a + b) = - a - b

- (w^{2} + 5 w - 4) = - w^{2} - 5 w + 4

= 4 w^{2} + 17 - w^{2} - 5 w + 4

Group like terms

= 4 w^{2} - w^{2} - 5 w + 17 + 4

Add similar elements:

4 w^{2} - w^{2} = 3 w^{2}

= 3 w^{2} - 5 w + 17 + 4

Add the numbers:

17 + 4 = 21

= 3 w^{2} - 5 w + 21

(x^{2} + 2) (m - n) + 2 (m - n)

x^{5} + 2 x^{3} + x^{2} + 2

\frac{21}{98}

\frac{3}{1} + \frac{1}{2}

csc (x) sec (x) - tan (x)

What is (4w^2+17)-(w^2+5w-4) ?
The solution to (4w^2+17)-(w^2+5w-4) is 3w^2-5w+21