What is factor x^{32}-1 ?

The solution to factor x^{32}-1 is (x^{16}+1)(x^8+1)(x^4+1)(x^2+1)(x+1)(x-1)

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factor x^{32}-1

factor

x^{32} - 1

(x^{16} + 1) (x^{8} + 1) (x^{4} + 1) (x^{2} + 1) (x + 1) (x - 1)

Solution steps

x^{32} - 1

Apply exponent rules

= (x^{16})^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x^{16})^{2} - 1^{2} = (x^{16} + 1) (x^{16} - 1)

= (x^{16} + 1) (x^{16} - 1)

Factor

x^{16} - 1 : (x^{8} + 1) (x^{4} + 1) (x^{2} + 1) (x + 1) (x - 1)

= (x^{16} + 1) (x^{8} + 1) (x^{4} + 1) (x^{2} + 1) (x + 1) (x - 1)

\frac{35}{100}

(4 x - 3 y) (5 x - 2 y)

3 (x + 1) (x - 1)

\frac{220}{3}

x^{3} + 12 x^{2} + 36 x

What is factor x^{32}-1 ?
The solution to factor x^{32}-1 is (x^{16}+1)(x^8+1)(x^4+1)(x^2+1)(x+1)(x-1)