What are the solutions to the equation 8+(x+3)^2=0 ?

The solutions to the equation 8+(x+3)^2=0 are x=2sqrt(2)i-3,x=-2sqrt(2)i-3

Find the zeros of 8+(x+3)^2=0

The zeros of 8+(x+3)^2=0 are x=2sqrt(2)i-3,x=-2sqrt(2)i-3

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8 + (x + 3)^{2} = 0

x = 22 i - 3, x = - 22 i - 3

Solution steps

8 + (x + 3)^{2} = 0

Move

8

to the right side

(x + 3)^{2} = - 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = - 8 : x = 22 i - 3

Solve

x + 3 = - - 8 : x = - 22 i - 3

The solutions to the quadratic equation are:

x = 22 i - 3, x = - 22 i - 3

- 3 (\frac{1}{2})

b^{2} - 4 b - 5 = 0

72 x^{2} - 120 x + 50

(z + 4)^{2} = 3

(64 v^{3})^{\frac{4}{3}}

What are the solutions to the equation 8+(x+3)^2=0 ?
The solutions to the equation 8+(x+3)^2=0 are x=2sqrt(2)i-3,x=-2sqrt(2)i-3
Find the zeros of 8+(x+3)^2=0
The zeros of 8+(x+3)^2=0 are x=2sqrt(2)i-3,x=-2sqrt(2)i-3