What is 1/(sqrt(s^2+1)) ?

The solution to 1/(sqrt(s^2+1)) is (sqrt(s^2+1))/(s^2+1)

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simplify 1/(sqrt(s^2+1))

simplify

\frac{1}{s ^{2} + 1}

\frac{s ^{2} + 1}{s ^{2} + 1}

Solution steps

\frac{1}{s ^{2} + 1}

Multiply by the conjugate

\frac{s ^{2} + 1}{s ^{2} + 1}

= \frac{1 \cdot s ^{2} + 1}{s ^{2} + 1 s ^{2} + 1}

1 \cdot s^{2} + 1 = s^{2} + 1

s^{2} + 1 s^{2} + 1 = s^{2} + 1

= \frac{s ^{2} + 1}{s ^{2} + 1}

\frac{1}{tan ( θ )}

\frac{14}{9} + \frac{7}{12} \cdot \frac{4}{21}

\frac{6 ^{\frac{1}{3}}}{6 ^{\frac{10}{3}}}

+ x^{2} - 6 x

- 3 a + 5 a - 10 a

What is 1/(sqrt(s^2+1)) ?
The solution to 1/(sqrt(s^2+1)) is (sqrt(s^2+1))/(s^2+1)