What is 4(x-5)^2+3(x-5) ?

The solution to 4(x-5)^2+3(x-5) is 4x^2-37x+85

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simplify 4(x-5)^2+3(x-5)

simplify

4 (x - 5)^{2} + 3 (x - 5)

4 x^{2} - 37 x + 85

Solution steps

4 (x - 5)^{2} + 3 (x - 5)

Expand

4 (x - 5)^{2} : 4 x^{2} - 40 x + 100

= 4 x^{2} - 40 x + 100 + 3 (x - 5)

Expand

3 (x - 5) : 3 x - 15

= 4 x^{2} - 40 x + 100 + 3 x - 15

Group like terms

= 4 x^{2} - 40 x + 3 x + 100 - 15

Add similar elements:

- 40 x + 3 x = - 37 x

= 4 x^{2} - 37 x + 100 - 15

Subtract the numbers:

100 - 15 = 85

= 4 x^{2} - 37 x + 85

(b + 1) (b - 1)

- sin^{2} (x)

\frac{( 7 x + 2 ) ^{2}}{7 x + 2 - 5}

4 \frac{1}{2} + 1 \frac{3}{5}

\frac{20000}{4 π \cdot ( 7.5 \cdot 1 0 ^{- 3} ) ^{2}}