What is (8a+4b)/(bc+2ac) ?

The solution to (8a+4b)/(bc+2ac) is 4/c

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simplify (8a+4b)/(bc+2ac)

simplify

\frac{8 a + 4 b}{b c + 2 a c}

\frac{4}{c}

Solution steps

\frac{8 a + 4 b}{b c + 2 a c}

Factor

8 a + 4 b : 4 (2 a + b)

= \frac{4 ( 2 a + b )}{b c + 2 a c}

Factor out common term

c

= \frac{4 ( 2 a + b )}{c ( b + 2 a )}

Apply the commutative law:

b + 2 a = 2 a + b

= \frac{4 ( 2 a + b )}{c ( 2 a + b )}

Cancel the common factor:

2 a + b

= \frac{4}{c}

64 m^{9} - 64 n^{16}

2 5^{6}

\frac{x}{x + 2} - \frac{6}{x - 3}

\frac{1}{2} + \frac{1}{9}