What is (x^2-4)/(3x)*6/(2x+4) ?

The solution to (x^2-4)/(3x)*6/(2x+4) is (x-2)/x

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simplify (x^2-4)/(3x)*6/(2x+4)

simplify

\frac{x ^{2} - 4}{3 x} \cdot \frac{6}{2 x + 4}

\frac{x - 2}{x}

Solution steps

\frac{x ^{2} - 4}{3 x} \cdot \frac{6}{2 x + 4}

Cancel

\frac{6}{2 x + 4} : \frac{3}{x + 2}

= \frac{x ^{2} - 4}{3 x} \cdot \frac{3}{x + 2}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x ^{2} - 4 ) \cdot 3}{3 x ( x + 2 )}

Cancel the common factor:

3

= \frac{x ^{2} - 4}{x ( x + 2 )}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{( x + 2 ) ( x - 2 )}{x ( x + 2 )}

Cancel the common factor:

x + 2

= \frac{x - 2}{x}

(x^{2} - 6 x + 1) (x - 3)

p^{2} - 49

\frac{5}{6} + \frac{8}{3}

\frac{1}{2} cos (2 x)

2^{3} \cdot 2^{2} \cdot 2^{- 4}

What is (x^2-4)/(3x)*6/(2x+4) ?
The solution to (x^2-4)/(3x)*6/(2x+4) is (x-2)/x