What is expand (-sin(2t)+2tcos(2t))^2 ?

The solution to expand (-sin(2t)+2tcos(2t))^2 is sin^2(2t)-4tcos(2t)sin(2t)+4t^2cos^2(2t)

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expand (-sin(2t)+2tcos(2t))^2

expand

(- sin (2 t) + 2 t cos (2 t))^{2}

sin^{2} (2 t) - 4 t cos (2 t) sin (2 t) + 4 t^{2} cos^{2} (2 t)

Solution steps

(- sin (2 t) + 2 t cos (2 t))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(- sin (2 t) + 2 t cos (2 t))^{2} = (- sin (2 t))^{2} + 2 (- sin (2 t)) \cdot 2 t cos (2 t) + (2 t cos (2 t))^{2}

= (- sin (2 t))^{2} + 2 (- sin (2 t)) \cdot 2 t cos (2 t) + (2 t cos (2 t))^{2}

Simplify

(- sin (2 t))^{2} + 2 (- sin (2 t)) \cdot 2 t cos (2 t) + (2 t cos (2 t))^{2} : sin^{2} (2 t) - 4 t cos (2 t) sin (2 t) + 4 t^{2} cos^{2} (2 t)

= sin^{2} (2 t) - 4 t cos (2 t) sin (2 t) + 4 t^{2} cos^{2} (2 t)

1.03 \cdot 0.9 \cdot 1.09 \cdot 0.98

\frac{3 ( a + b ) + 4 ( a - b ) - 7 ( a - b )}{b + 2 b + 3 b}

\frac{3}{21} + \frac{1}{2} + \frac{2}{49}

2 lo g_{10} (5) + lo g_{10} (7) - 3 lo g_{10} (2)

- 32 (4^{- 2}) + (\frac{∣ - 18 ∣}{2 + 10 4})

What is expand (-sin(2t)+2tcos(2t))^2 ?
The solution to expand (-sin(2t)+2tcos(2t))^2 is sin^2(2t)-4tcos(2t)sin(2t)+4t^2cos^2(2t)