What is 1/(x+1)-1/(x+2) ?

The solution to 1/(x+1)-1/(x+2) is 1/((x+1)(x+2))

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simplify 1/(x+1)-1/(x+2)

simplify

\frac{1}{x + 1} - \frac{1}{x + 2}

\frac{1}{( x + 1 ) ( x + 2 )}

Solution steps

\frac{1}{x + 1} - \frac{1}{x + 2}

Least Common Multiplier of

x + 1, x + 2 : (x + 1) (x + 2)

Adjust Fractions based on the LCM

= \frac{x + 2}{( x + 1 ) ( x + 2 )} - \frac{x + 1}{( x + 1 ) ( x + 2 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{x + 2 - ( x + 1 )}{( x + 1 ) ( x + 2 )}

Simplify

x + 2 - (x + 1) : 1

= \frac{1}{( x + 1 ) ( x + 2 )}

(x y)^{- 3}

\frac{- 9 + 5 i}{- 7 - 6 i}

- 1 - 3 i

3^{4 x}

(\frac{1 + 2 i}{1 - 2 i} + \frac{2 + i}{1 + 2 i}) \cdot 1 - i