What are the solutions to the equation u^2+u-20=0 ?

The solutions to the equation u^2+u-20=0 are u=4,u=-5

Find the zeros of u^2+u-20=0

The zeros of u^2+u-20=0 are u=4,u=-5

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u^{2} + u - 20 = 0

u = 4, u = - 5

Solution steps

u^{2} + u - 20 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 20) = 9

u_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 1 + 9}{2 \cdot 1}, u_{2} = \frac{- 1 - 9}{2 \cdot 1}

u = \frac{- 1 + 9}{2 \cdot 1} : 4

u = \frac{- 1 - 9}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

u = 4, u = - 5

x^{2} + 14 + 24

C - 12 = - 24

4 + \frac{x + 5}{8} = 20

12 x^{2} - 22 x - 20

∣ 2 x + 4 ∣ > 5

What are the solutions to the equation u^2+u-20=0 ?
The solutions to the equation u^2+u-20=0 are u=4,u=-5
Find the zeros of u^2+u-20=0
The zeros of u^2+u-20=0 are u=4,u=-5