What is expand (x+2)(x-4)(3x+2) ?

The solution to expand (x+2)(x-4)(3x+2) is 3x^3-4x^2-28x-16

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expand (x+2)(x-4)(3x+2)

expand

(x + 2) (x - 4) (3 x + 2)

3 x^{3} - 4 x^{2} - 28 x - 16

Solution steps

(x + 2) (x - 4) (3 x + 2)

Expand

(x + 2) (x - 4) (3 x + 2) : (x^{2} - 2 x - 8) (3 x + 2)

= (x^{2} - 2 x - 8) (3 x + 2)

Distribute parentheses

= x^{2} \cdot 3 x + x^{2} \cdot 2 - 2 x \cdot 3 x - 2 x \cdot 2 - 8 \cdot 3 x - 8 \cdot 2

Simplify

x^{2} \cdot 3 x + x^{2} \cdot 2 - 2 x \cdot 3 x - 2 x \cdot 2 - 8 \cdot 3 x - 8 \cdot 2 : 3 x^{3} - 4 x^{2} - 28 x - 16

= 3 x^{3} - 4 x^{2} - 28 x - 16

m^{8}

\frac{2 cos ^{2} ( x ) - cos ( x ) - 1}{cos ( x ) - 1}

\frac{1}{2} \cdot 9 \cdot 7

a (x - 1) - (a + 2) (x - 1)

(3)^{2} + (5)^{2}

What is expand (x+2)(x-4)(3x+2) ?
The solution to expand (x+2)(x-4)(3x+2) is 3x^3-4x^2-28x-16