What is expand (x-3)(x+2)(x-4) ?

The solution to expand (x-3)(x+2)(x-4) is x^3-5x^2-2x+24

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expand (x-3)(x+2)(x-4)

expand

(x - 3) (x + 2) (x - 4)

x^{3} - 5 x^{2} - 2 x + 24

Solution steps

(x - 3) (x + 2) (x - 4)

Expand

(x - 3) (x + 2) (x - 4) : (x^{2} - x - 6) (x - 4)

= (x^{2} - x - 6) (x - 4)

Distribute parentheses

= x^{2} x + x^{2} (- 4) - xx - x (- 4) - 6 x - 6 (- 4)

Simplify

x^{2} x + x^{2} (- 4) - xx - x (- 4) - 6 x - 6 (- 4) : x^{3} - 5 x^{2} - 2 x + 24

= x^{3} - 5 x^{2} - 2 x + 24

(b + 3)^{2}

\frac{24}{24}

3 x + 30

lo g_{10} (180)

2 - \frac{3}{8}

What is expand (x-3)(x+2)(x-4) ?
The solution to expand (x-3)(x+2)(x-4) is x^3-5x^2-2x+24