What are the solutions to the equation y^2-y-20=0 ?

The solutions to the equation y^2-y-20=0 are y=5,y=-4

Find the zeros of y^2-y-20=0

The zeros of y^2-y-20=0 are y=5,y=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - y - 20 = 0

y = 5, y = - 4

Solution steps

y^{2} - y - 20 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

y_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, y_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

y = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

y = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

y = 5, y = - 4

\frac{\frac{1}{2}}{- \frac{3}{2}}

x^{2} \leq 6 x - 4

(4)^{2}

ln (x^{y})

2 x^{2} + 54 = 0

What are the solutions to the equation y^2-y-20=0 ?
The solutions to the equation y^2-y-20=0 are y=5,y=-4
Find the zeros of y^2-y-20=0
The zeros of y^2-y-20=0 are y=5,y=-4