What is ((16pq^2)/q)/((8p^3-16p)) ?

The solution to ((16pq^2)/q)/((8p^3-16p)) is (2q)/(p^2-2)

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simplify ((16pq^2)/q)/((8p^3-16p))

simplify

\frac{\frac{16 p q ^{2}}{q}}{( 8 p ^{3} - 16 p )}

\frac{2 q}{p ^{2} - 2}

Solution steps

\frac{\frac{16 p q ^{2}}{q}}{8 p ^{3} - 16 p}

Cancel

\frac{16 p q ^{2}}{q} : 16 pq

= \frac{16 pq}{8 p ^{3} - 16 p}

Factor

8 p^{3} - 16 p : 8 p (p^{2} - 2)

= \frac{16 pq}{8 p ( p ^{2} - 2 )}

Cancel the common factor:

p

= \frac{16 q}{8 ( p ^{2} - 2 )}

Factor the number:

16 = 8 \cdot 2

= \frac{8 \cdot 2 q}{8 ( p ^{2} - 2 )}

Cancel the common factor:

8

= \frac{2 q}{p ^{2} - 2}

(3 a)^{0} - 5 a^{0}

\frac{( x ^{2} + 3 x + 5 ) ^{n} + x ^{2} ( x + 3 ) ^{2} + 3}{x ^{2} + 3 x + 4}

(2 x e^{y} + e^{x}) d x + (x^{2} + 1) e^{y} d y

(x^{2} y^{2} + 1) d x + 2 x^{2} d y

(2, 5) y (0, - 3)

What is ((16pq^2)/q)/((8p^3-16p)) ?
The solution to ((16pq^2)/q)/((8p^3-16p)) is (2q)/(p^2-2)