What is (\partial)/(\partial y)((z)(x^2e^y-yze^x)) ?

The answer to (\partial)/(\partial y)((z)(x^2e^y-yze^x)) is z(x^2e^y-ze^x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)((z)(x^2e^y-yze^x))

\frac{\partial}{\partial y} ((z) (x^{2} e^{y} - yz e^{x}))

z (x^{2} e^{y} - z e^{x})

Solution steps

\frac{\partial}{\partial y} ((z) (x^{2} e^{y} - yz e^{x}))

Treat

z, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{\partial}{\partial y} (x^{2} e^{y} - yz e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{\partial}{\partial y} (x^{2} e^{y}) - \frac{\partial}{\partial y} (yz e^{x}))

\frac{\partial}{\partial y} (x^{2} e^{y}) = x^{2} e^{y}

\frac{\partial}{\partial y} (yz e^{x}) = z e^{x}

= z (x^{2} e^{y} - z e^{x})

\frac{15}{s ( s + 3 )}

l (- 5 e - 2 t + cos (8 t) + 1)

[(x - 2) e^{x}] d x

\frac{8 x ^{2} + 9}{( x + 7 ) ^{3}}

What is (\partial)/(\partial y)((z)(x^2e^y-yze^x)) ?
The answer to (\partial)/(\partial y)((z)(x^2e^y-yze^x)) is z(x^2e^y-ze^x)