What is expand (1-e^{-at})sin(x) ?

The solution to expand (1-e^{-at})sin(x) is sin(x)-e^{-at}sin(x)

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expand (1-e^{-at})sin(x)

expand

(1 - e^{- a t}) sin (x)

sin (x) - e^{- a t} sin (x)

Solution steps

(1 - e^{- a t}) sin (x)

= sin (x) (1 - e^{- a t})

Apply the distributive law:

a (b - c) = ab - a c

a = sin (x), b = 1, c = e^{- a t}

= sin (x) \cdot 1 - sin (x) e^{- a t}

= 1 \cdot sin (x) - e^{- a t} sin (x)

Multiply:

1 \cdot sin (x) = sin (x)

= sin (x) - e^{- a t} sin (x)

\frac{( x - 1 ) ^{4 n} ( x ^{3} + 8 ) ( x - 4 )}{( x ^{2} - 2 x + 2 )}

A B + A (C D + C D^{^{'}})

A (1, 3) B (2, - 5)

(3 e^{3 t} + 4 e^{- 4 t})^{3}

\frac{x ^{2} - 2 x + 3}{( x - 3 ) ( x ^{2} + 9 )}

What is expand (1-e^{-at})sin(x) ?
The solution to expand (1-e^{-at})sin(x) is sin(x)-e^{-at}sin(x)