What is expand 4u(t-pi)sin(t) ?

The solution to expand 4u(t-pi)sin(t) is 4utsin(t)-4piusin(t)

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expand 4u(t-pi)sin(t)

expand

4 u (t - π) sin (t)

4 u t sin (t) - 4 π u sin (t)

Solution steps

4 u (t - π) sin (t)

= 4 u sin (t) (t - π)

Apply the distributive law:

a (b - c) = ab - a c

a = 4 u sin (t), b = t, c = π

= 4 u sin (t) t - 4 u sin (t) π

= 4 u t sin (t) - 4 π u sin (t)

\frac{15 - 3 x}{( 2 x - 4 ) ( x + 3 )}

- \frac{1}{2} (cos (x) + sin (x)) + c e^{x}

\frac{x ^{4} - 4 x ^{3} + 6 x ^{2} - ( a + 2 ) x + ( b + 3 )}{x ^{2} + 2 x + 1}

- 2 x \cdot (3 x^{4}) - 11 x

\frac{e ^{- 2 s}}{s ^{2} ( s - 1 )}

What is expand 4u(t-pi)sin(t) ?
The solution to expand 4u(t-pi)sin(t) is 4utsin(t)-4piusin(t)