What is expand (6x^2-x+1)/((x-1)(x+2)(x-3)) ?

The solution to expand (6x^2-x+1)/((x-1)(x+2)(x-3)) is (6x^2-x+1)/(x^3-2x^2-5x+6)

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expand (6x^2-x+1)/((x-1)(x+2)(x-3))

expand

\frac{6 x ^{2} - x + 1}{( x - 1 ) ( x + 2 ) ( x - 3 )}

\frac{6 x ^{2} - x + 1}{x ^{3} - 2 x ^{2} - 5 x + 6}

Solution steps

\frac{6 x ^{2} - x + 1}{( x - 1 ) ( x + 2 ) ( x - 3 )}

Expand

(x - 1) (x + 2) (x - 3) : x^{3} - 2 x^{2} - 5 x + 6

= \frac{6 x ^{2} - x + 1}{x ^{3} - 2 x ^{2} - 5 x + 6}

\frac{2 x ^{3} + ( 1 - 2 a ) x ^{2} + ( 1 - a ) x - a}{x - a}

2 (y + x \frac{d y}{d x})

\frac{36 x}{( x - 1 ) ^{2}}

\frac{2}{( x - 1 ) ^{2}}

(x^{2} + 2 x) d x

What is expand (6x^2-x+1)/((x-1)(x+2)(x-3)) ?
The solution to expand (6x^2-x+1)/((x-1)(x+2)(x-3)) is (6x^2-x+1)/(x^3-2x^2-5x+6)