What is expand (A+B)(A^'+C)(B+C) ?

The solution to expand (A+B)(A^'+C)(B+C) is BA^{1+'}+CA^{1+'}+ABC+AC^2+B^2A^'+BCA^'+B^2C+BC^2

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expand (A+B)(A^'+C)(B+C)

expand

(A + B) (A^{^{'}} + C) (B + C)

B A^{1 +'} + C A^{1 +'} + A BC + A C^{2} + B^{2} A^{'} + BC A^{'} + B^{2} C + B C^{2}

Solution steps

(A + B) (A^{^{'}} + C) (B + C)

Expand

(A + B) (A^{^{'}} + C) : A^{1 +^{'}} + A C + B A^{^{'}} + BC

= (A^{1 +^{'}} + A C + B A^{^{'}} + BC) (B + C)

Expand

(A^{1 +^{'}} + A C + B A^{^{'}} + BC) (B + C) : B A^{1 +^{'}} + C A^{1 +^{'}} + A BC + A C^{2} + B^{2} A^{^{'}} + BC A^{^{'}} + B^{2} C + B C^{2}

= B A^{1 +^{'}} + C A^{1 +^{'}} + A BC + A C^{2} + B^{2} A^{^{'}} + BC A^{^{'}} + B^{2} C + B C^{2}

l (- 5 e^{- 2 t} + cos (8 t) + 1)

\frac{4 ( x - 2 )}{( x + 3 ) ^{3}}

\frac{x y ^{2}}{\frac{y}{3} \cdot \frac{1}{3 x}}

A (- 1, - 2)

\frac{( x - 3 ) ^{2} ( x + 2 )}{( x + 3 )}

What is expand (A+B)(A^'+C)(B+C) ?
The solution to expand (A+B)(A^'+C)(B+C) is BA^{1+'}+CA^{1+'}+ABC+AC^2+B^2A^'+BCA^'+B^2C+BC^2