What is expand (3x^3-4x+5)/((x-1)(x^2+2x+1)) ?

The solution to expand (3x^3-4x+5)/((x-1)(x^2+2x+1)) is (3x^3-4x+5)/(x^3+x^2-x-1)

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expand (3x^3-4x+5)/((x-1)(x^2+2x+1))

expand

\frac{3 x ^{3} - 4 x + 5}{( x - 1 ) ( x ^{2} + 2 x + 1 )}

\frac{3 x ^{3} - 4 x + 5}{x ^{3} + x ^{2} - x - 1}

Solution steps

\frac{3 x ^{3} - 4 x + 5}{( x - 1 ) ( x ^{2} + 2 x + 1 )}

Expand

(x - 1) (x^{2} + 2 x + 1) : x^{3} + x^{2} - x - 1

= \frac{3 x ^{3} - 4 x + 5}{x ^{3} + x ^{2} - x - 1}

\frac{2 x ^{2} + x + 8}{( x ^{2} + 4 ) ^{2}}

(1 + y^{2}) d x

\frac{( 3 - 5 + x ) ( 1 + 5 - x )}{x - 4}

\frac{x ^{3} - x - 1}{( x + 1 ) ^{2}}

\frac{n + ( - 1 ) ^{n}}{n}

What is expand (3x^3-4x+5)/((x-1)(x^2+2x+1)) ?
The solution to expand (3x^3-4x+5)/((x-1)(x^2+2x+1)) is (3x^3-4x+5)/(x^3+x^2-x-1)