What are the solutions to the equation -x^2-4x-3=0 ?

The solutions to the equation -x^2-4x-3=0 are x=-3,x=-1

Find the zeros of -x^2-4x-3=0

The zeros of -x^2-4x-3=0 are x=-3,x=-1

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- x^{2} - 4 x - 3 = 0

x = - 3, x = - 1

Solution steps

- x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) ( - 3 )}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) (- 3) = 2

x_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 2}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 2}{2 ( - 1 )} : - 3

x = \frac{- ( - 4 ) - 2}{2 ( - 1 )} : - 1

The solutions to the quadratic equation are:

x = - 3, x = - 1

2 ∣ x + 1 ∣ + 5 = 1

- 5 - (- 8)

lo g_{9} (3) = x

- 7 y^{5} (13 x y^{2})

- 6 x^{2} (- x^{2} - 2 x - 2) \geq 0

What are the solutions to the equation -x^2-4x-3=0 ?
The solutions to the equation -x^2-4x-3=0 are x=-3,x=-1
Find the zeros of -x^2-4x-3=0
The zeros of -x^2-4x-3=0 are x=-3,x=-1