What is expand 1/2 (sqrt(2)-ln(sqrt(2)+1)) ?

The solution to expand 1/2 (sqrt(2)-ln(sqrt(2)+1)) is 1/(sqrt(2))-(ln(1+sqrt(2)))/2

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expand 1/2 (sqrt(2)-ln(sqrt(2)+1))

expand

\frac{1}{2} (2 - ln (2 + 1))

\frac{1}{2} - \frac{ln ( 1 + 2 )}{2}

Solution steps

\frac{1}{2} (2 - ln (2 + 1))

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{1}{2}, b = 2, c = ln (2 + 1)

= \frac{1}{2} 2 - \frac{1}{2} ln (2 + 1)

= 2 \frac{1}{2} - \frac{1}{2} ln (2 + 1)

Simplify

2 \frac{1}{2} - \frac{1}{2} ln (2 + 1) : \frac{1}{2} - \frac{ln ( 1 + 2 )}{2}

= \frac{1}{2} - \frac{ln ( 1 + 2 )}{2}

(2 q + r)^{\frac{2}{3}}

2 sin (\frac{π}{3} (x - 4)) + 6

\frac{d}{d x} ((x - π) e^{x - π}) + sin (x)

(5 e^{3} + 3 f^{2})^{6}

(- 2, 7) y (0, - 3)

What is expand 1/2 (sqrt(2)-ln(sqrt(2)+1)) ?
The solution to expand 1/2 (sqrt(2)-ln(sqrt(2)+1)) is 1/(sqrt(2))-(ln(1+sqrt(2)))/2