What is expand (3t-1)^2dt ?

The solution to expand (3t-1)^2dt is 9t^2dt-6tdt+dt

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expand (3t-1)^2dt

expand

(3 t - 1)^{2} d t

9 t^{2} d t - 6 t d t + d t

Solution steps

(3 t - 1)^{2} d t

(3 t - 1)^{2} = 9 t^{2} - 6 t + 1

= (9 t^{2} - 6 t + 1) d t

Distribute parentheses

= d t \cdot 9 t^{2} + d t (- 6 t) + d t \cdot 1

Apply minus-plus rules

+ (- a) = - a

= 9 t^{2} d t - 6 t d t + 1 \cdot d t

Multiply:

1 \cdot d t = d t

= 9 t^{2} d t - 6 t d t + d t

\frac{5}{( 2 x + 5 ) ^{2}}

e^{(9 x)} (4 - x)

\frac{S}{( S ^{2} + 4 ) ^{3}}

l im x \Rightarrow 2 (5 x^{2} - 3 x + 1)

\frac{s ^{3} + 5 s ^{2} + 9 s + 7}{( s + 1 ) ( s + 2 )}