What is (\partial)/(\partial x)((y)(y-x)) ?

The answer to (\partial)/(\partial x)((y)(y-x)) is -y

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(\partial)/(\partial x)((y)(y-x))

\frac{\partial}{\partial x} ((y) (y - x))

- y

Solution steps

\frac{\partial}{\partial x} ((y) (y - x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (y - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= y (\frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (x))

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (x) = 1

= y (0 - 1)

Simplify

= - y

\frac{\partial}{\partial a} ((x) (a x^{5} + b x + 3))

A (6, - 8) B (4, 2)

(e^{2 x} + 1)^{3}

\frac{5 x - 1}{( x + 1 ) ( x - 2 )}

- \frac{1}{2} (cos (x) + sin (x)) + C e^{x}

What is (\partial)/(\partial x)((y)(y-x)) ?
The answer to (\partial)/(\partial x)((y)(y-x)) is -y