What is expand (2x^4-6x^2+12)/((x+1)(x-1)) ?

The solution to expand (2x^4-6x^2+12)/((x+1)(x-1)) is (2x^4-6x^2+12)/(x^2-1)

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expand (2x^4-6x^2+12)/((x+1)(x-1))

expand

\frac{2 x ^{4} - 6 x ^{2} + 12}{( x + 1 ) ( x - 1 )}

\frac{2 x ^{4} - 6 x ^{2} + 12}{x ^{2} - 1}

Solution steps

\frac{2 x ^{4} - 6 x ^{2} + 12}{( x + 1 ) ( x - 1 )}

Expand

(x + 1) (x - 1) : x^{2} - 1

= \frac{2 x ^{4} - 6 x ^{2} + 12}{x ^{2} - 1}

\frac{d}{d x} (3 x cos (2 x)) + (3 x^{2} - 5) sin (2 x)

A (- 4, - 2) y B (5, 3)

\frac{4 m n ^{2} + p n ^{2}}{32 km + 8 k p}

\frac{( 4 + x ^{2} ) ^{2}}{2}

\frac{3 s ^{2} + s - 23}{( s + 3 ) ( 3 s - 2 ) ( s - 1 )}

What is expand (2x^4-6x^2+12)/((x+1)(x-1)) ?
The solution to expand (2x^4-6x^2+12)/((x+1)(x-1)) is (2x^4-6x^2+12)/(x^2-1)