What is expand (6x^3-5x^2)/((x^2-3)^2) ?

The solution to expand (6x^3-5x^2)/((x^2-3)^2) is (6x^3-5x^2)/(x^4-6x^2+9)

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expand (6x^3-5x^2)/((x^2-3)^2)

expand

\frac{6 x ^{3} - 5 x ^{2}}{( x ^{2} - 3 ) ^{2}}

\frac{6 x ^{3} - 5 x ^{2}}{x ^{4} - 6 x ^{2} + 9}

Solution steps

\frac{6 x ^{3} - 5 x ^{2}}{( x ^{2} - 3 ) ^{2}}

(x^{2} - 3)^{2} = x^{4} - 6 x^{2} + 9

= \frac{6 x ^{3} - 5 x ^{2}}{x ^{4} - 6 x ^{2} + 9}

\frac{x ^{2} + 2 x + 3}{( x - 1 ) ^{2} ( x - 2 ) ( x ^{2} + 4 )}

- \frac{2 ( 4 + 6 )}{5}

e^{t} θ (t - 2)

\frac{a x ^{3} + ( 2 a + 1 ) x + 1}{a x + 3 a}

\frac{7}{( 2 + j ) ^{2}}

What is expand (6x^3-5x^2)/((x^2-3)^2) ?
The solution to expand (6x^3-5x^2)/((x^2-3)^2) is (6x^3-5x^2)/(x^4-6x^2+9)