What is expand sqrt((2pi-4\sqrt{5))^2} ?

The solution to expand sqrt((2pi-4\sqrt{5))^2} is 2sqrt(pi^2-4\sqrt{5)pi+20}

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expand sqrt((2pi-4\sqrt{5))^2}

expand

(2 π - 45)^{2}

2 π^{2} - 45 π + 20

Decimal Notation

2.66108 \dots

Solution steps

(2 π - 45)^{2}

(2 π - 45)^{2} = 4 π^{2} - 165 π + 80

= 4 π^{2} - 165 π + 80

Factor

4 π^{2} - 165 π + 80 : 4 (π^{2} - 45 π + 20)

= 4 (π^{2} - 45 π + 20)

Apply radical rule:

assuming

a \geq 0, b \geq 0

= 4 π^{2} - 45 π + 20

4 = 2

= 2 π^{2} - 45 π + 20

U (t - 4) (2 - t^{2}) + 2 e^{- π t} + sin (3 t) - t^{3}

\frac{( x ^{4} - 1 ) ^{2}}{4 x ^{4}}

(4 x^{3} y^{2} - 6 x^{2} y - 2 x - 3) d x + (2 x^{4} y - 2 x^{3}) d y

(k + 1)! (k + 2)

\frac{1}{( x + 1 ) ( x + 2 ) ^{2} ( x ^{2} + 1 ) ( x ^{2} + 2 ) ^{2}}

What is expand sqrt((2pi-4\sqrt{5))^2} ?
The solution to expand sqrt((2pi-4\sqrt{5))^2} is 2sqrt(pi^2-4\sqrt{5)pi+20}