What is expand 1/((s-2)(s^2+3)) ?

The solution to expand 1/((s-2)(s^2+3)) is 1/(s^3+3s-2s^2-6)

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expand 1/((s-2)(s^2+3))

expand

\frac{1}{( s - 2 ) ( s ^{2} + 3 )}

\frac{1}{s ^{3} + 3 s - 2 s ^{2} - 6}

Solution steps

\frac{1}{( s - 2 ) ( s ^{2} + 3 )}

Expand

(s - 2) (s^{2} + 3) : s^{3} + 3 s - 2 s^{2} - 6

= \frac{1}{s ^{3} + 3 s - 2 s ^{2} - 6}

\frac{2 x ^{2} + 3}{( x ^{2} + 1 ) ^{2}}

\frac{( 3 x + 4 ) ^{3}}{9}

U (t - 4) (2 - t^{2}) + 3 e^{- π t} + sin (5 t) - t^{3}

9 (π + 1)

(A + B) (C + B) (D^{^{'}} + B) (A C D^{^{'}} + E)

What is expand 1/((s-2)(s^2+3)) ?
The solution to expand 1/((s-2)(s^2+3)) is 1/(s^3+3s-2s^2-6)