What are the solutions to the equation x^2-35x+300=0 ?

The solutions to the equation x^2-35x+300=0 are x=20,x=15

Find the zeros of x^2-35x+300=0

The zeros of x^2-35x+300=0 are x=20,x=15

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x^{2} - 35 x + 300 = 0

x = 20, x = 15

Solution steps

x^{2} - 35 x + 300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 35 ) \pm ( - 35 ) ^{2} - 4 \cdot 1 \cdot 300}{2 \cdot 1}

(- 35)^{2} - 4 \cdot 1 \cdot 300 = 5

x_{1, 2} = \frac{- ( - 35 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 35 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 35 ) - 5}{2 \cdot 1}

x = \frac{- ( - 35 ) + 5}{2 \cdot 1} : 20

x = \frac{- ( - 35 ) - 5}{2 \cdot 1} : 15

The solutions to the quadratic equation are:

x = 20, x = 15

- \frac{5}{8} + \frac{1}{2}

4 ∣ x - 1 ∣ + 2 > 6

\frac{x ^{- 1}}{( x y ) ^{3}}

2.8 d^{2} - 0.44 d - 0.0484 = 0

\frac{1}{81}

What are the solutions to the equation x^2-35x+300=0 ?
The solutions to the equation x^2-35x+300=0 are x=20,x=15
Find the zeros of x^2-35x+300=0
The zeros of x^2-35x+300=0 are x=20,x=15