What is expand x/((x^2+4)(x-3)) ?

The solution to expand x/((x^2+4)(x-3)) is x/(x^3-3x^2+4x-12)

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expand x/((x^2+4)(x-3))

expand

\frac{x}{( x ^{2} + 4 ) ( x - 3 )}

\frac{x}{x ^{3} - 3 x ^{2} + 4 x - 12}

Solution steps

\frac{x}{( x ^{2} + 4 ) ( x - 3 )}

Expand

(x^{2} + 4) (x - 3) : x^{3} - 3 x^{2} + 4 x - 12

= \frac{x}{x ^{3} - 3 x ^{2} + 4 x - 12}

\frac{( 1 + 2 x ) ^{4}}{4}

\frac{1}{x f ( x ^{2} - 5 x )}

3 (x^{6})

\frac{3 x y}{( x ^{2} - 2 ) ( y ^{2} + 3 )}

3 (e^{x} + e^{x} x)

What is expand x/((x^2+4)(x-3)) ?
The solution to expand x/((x^2+4)(x-3)) is x/(x^3-3x^2+4x-12)