What is expand (j-1)/((j+2)(j+4)) ?

The solution to expand (j-1)/((j+2)(j+4)) is (j-1)/(j^2+6j+8)

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expand (j-1)/((j+2)(j+4))

expand

\frac{j - 1}{( j + 2 ) ( j + 4 )}

\frac{j - 1}{j ^{2} + 6 j + 8}

Solution steps

\frac{j - 1}{( j + 2 ) ( j + 4 )}

Expand

(j + 2) (j + 4) : j^{2} + 6 j + 8

= \frac{j - 1}{j ^{2} + 6 j + 8}

\frac{7 x + 25}{( x + 4 ) ( x + 3 )}

\frac{d}{d t} ((z (t, x, y)) (x^{2} + y^{5}))

\frac{9 x - 8}{( x - 3 ) ( 2 x - 5 )}

\frac{1}{4} (e^{2 x} + e^{- 2 x})

\frac{( x ^{2} + x + 3 ) ^{n} + x ^{2} ( x + 1 ) ^{2} + 3}{x ^{2} + x + 2}

What is expand (j-1)/((j+2)(j+4)) ?
The solution to expand (j-1)/((j+2)(j+4)) is (j-1)/(j^2+6j+8)