What is expand ((2x-1)(x+2))/2 ?

The solution to expand ((2x-1)(x+2))/2 is x^2+(3x)/2-1

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expand ((2x-1)(x+2))/2

expand

\frac{( 2 x - 1 ) ( x + 2 )}{2}

x^{2} + \frac{3 x}{2} - 1

Solution steps

\frac{( 2 x - 1 ) ( x + 2 )}{2}

Expand

(2 x - 1) (x + 2) : 2 x^{2} + 3 x - 2

= \frac{2 x ^{2} + 3 x - 2}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} + 3 x - 2}{2} = \frac{2 x ^{2}}{2} + \frac{3 x}{2} - \frac{2}{2}

= \frac{2 x ^{2}}{2} + \frac{3 x}{2} - \frac{2}{2}

Apply rule

\frac{a}{a} = 1

\frac{2}{2} = 1

= \frac{2 x ^{2}}{2} + \frac{3 x}{2} - 1

Divide the numbers:

\frac{2}{2} = 1

= x^{2} + \frac{3 x}{2} - 1

(- 1, 5) y (2, - 1)

\frac{x ^{2} - 2 x + k - 2}{( x - 1 ) ^{2} ( x + 2 )}

x + 1 + (x + 1) e^{- 2 x}

1 1^{l o g_{10} (11) (3 x - 2)}

(1 - p + p \cdot e^{t})^{3}

What is expand ((2x-1)(x+2))/2 ?
The solution to expand ((2x-1)(x+2))/2 is x^2+(3x)/2-1