What is expand (-2x+3y)/(3(y^2-x)) ?

The solution to expand (-2x+3y)/(3(y^2-x)) is (-2x+3y)/(3y^2-3x)

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expand (-2x+3y)/(3(y^2-x))

expand

\frac{- 2 x + 3 y}{3 ( y ^{2} - x )}

\frac{- 2 x + 3 y}{3 y ^{2} - 3 x}

Solution steps

\frac{- 2 x + 3 y}{3 ( y ^{2} - x )}

Expand

3 (y^{2} - x) : 3 y^{2} - 3 x

= \frac{- 2 x + 3 y}{3 y ^{2} - 3 x}

2 (e^{x^{2}} + 2 e^{x^{2}} x^{2}) + e^{x^{2}} \cdot 2 x

\frac{8 s ^{2} - s + 1}{s ( s - 1 ) ( s + 4 ) ( s - 4 )}

\frac{2 ( x + y ^{4} ) ^{5}}{y ^{20}}

\frac{x - 5}{( x - 1 ) ( x - 2 )}

\frac{n ( n - 1 ) ( n - 2 ) ( n - 3 )}{24}

What is expand (-2x+3y)/(3(y^2-x)) ?
The solution to expand (-2x+3y)/(3(y^2-x)) is (-2x+3y)/(3y^2-3x)