What are the solutions to the equation (4y+6)^2=36 ?

The solutions to the equation (4y+6)^2=36 are y=0,y=-3

Find the zeros of (4y+6)^2=36

The zeros of (4y+6)^2=36 are y=0,y=-3

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(4 y + 6)^{2} = 36

y = 0, y = - 3

Solution steps

(4 y + 6)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 y + 6 = 36 : y = 0

Solve

4 y + 6 = - 36 : y = - 3

The solutions to the quadratic equation are:

y = 0, y = - 3

∣ 4 x - 2 ∣ = 14 ∣

\frac{( a x + a q ) ( a x + p )}{a}

(y)^{2}

\frac{x + 4}{2} - \frac{5}{6} = \frac{2 x - 2}{3}

\frac{5}{10}

What are the solutions to the equation (4y+6)^2=36 ?
The solutions to the equation (4y+6)^2=36 are y=0,y=-3
Find the zeros of (4y+6)^2=36
The zeros of (4y+6)^2=36 are y=0,y=-3