What is expand 1/((x-3)(x-2)(x-1)) ?

The solution to expand 1/((x-3)(x-2)(x-1)) is 1/(x^3-6x^2+11x-6)

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expand 1/((x-3)(x-2)(x-1))

expand

\frac{1}{( x - 3 ) ( x - 2 ) ( x - 1 )}

\frac{1}{x ^{3} - 6 x ^{2} + 11 x - 6}

Solution steps

\frac{1}{( x - 3 ) ( x - 2 ) ( x - 1 )}

Expand

(x - 3) (x - 2) (x - 1) : x^{3} - 6 x^{2} + 11 x - 6

= \frac{1}{x ^{3} - 6 x ^{2} + 11 x - 6}

\frac{1 + 2 x}{3 ( x - 3 )}

f oco (0, - 2)

\frac{\partial}{\partial x} ((z) (y x^{2} - x y))

(x + ln (x))^{4}

- \frac{3 ( x + 3 ) ( x - 1 )}{x ^{2}}

What is expand 1/((x-3)(x-2)(x-1)) ?
The solution to expand 1/((x-3)(x-2)(x-1)) is 1/(x^3-6x^2+11x-6)